
Current Electricity, Circuits & Kirchhoff’s Rules
Exam-focused theory, solved examples, past-paper concepts, formula revision and original MCQs.
Electric current and its physical meaning
Electric current is the rate at which electric charge passes through a selected cross-section. Average current I=ΔQ/Δt becomes instantaneous current I=dQ/dt when the rate changes. The ampere is the SI unit, equivalent to one coulomb per second. Current may arise through mobile electrons in metals, positive and negative ions in electrolytes, and electrons and holes in semiconductors. The definition is based on net charge crossing a surface rather than the speed of one particular charge carrier.
Conventional current is assigned the direction positive charges would move. In a metallic conductor electrons are negative, so their average drift is opposite conventional current. Do not confuse current with the very rapid microscopic random motion of electrons: random movement normally produces no net current until an electric field establishes a preferred average drift. In a steady circuit the charge flowing into a junction equals charge flowing out, unless charge is accumulating at the node. A 2 A current for 10 s transfers 20 C, corresponding to approximately 1.25×10²⁰ elementary charges.
Microscopic drift, mobility and current density
The free-electron model explains the electric current through the gradual drift of carriers in an applied electric field. For one carrier species with number density n, charge magnitude e, cross-sectional area A and average drift speed v_d, the current magnitude is I=neAv_d. Current density J=I/A for uniform flow gives the amount of current through each square metre of cross section. It is a vector in the direction of conventional current, which is opposite to electron drift in a typical metal.
Electron drift is extremely slow compared with the speed at which electrical signals or field changes propagate through a circuit. Mobility μ is the magnitude ratio v_d/E in a simple linear-response regime, and conductivity σ=neμ in a one-carrier model. An exceptionally thin wire carrying the same current has larger current density; this can increase heating and trigger practical current limits. The microscopic description assumes a suitable uniform material and should not be extended unchanged to devices having multiple carriers, strong fields or nonlinear conductivity.
Potential difference, electric energy and sources
Electric potential difference between two points is the change in electric potential energy per unit positive test charge, measured in volts or joules per coulomb. A source such as a battery maintains a potential difference by converting chemical energy into electrical energy. In an operating circuit, the field inside an ordinary resistive conductor drives drift, whereas an isolated conductor in electrostatic equilibrium has zero field inside its conducting material.
A complete circuit provides a path for sustained current, but voltage can exist across an open switch while no steady current flows through the break. A battery has finite stored energy and internal resistance; it is not a limitless current source. A voltmeter reads between two points, so it connects in parallel with the component being studied. An ammeter reads current through a particular branch, so it connects in series. The polarity of a meter determines the sign of its reading, and both meters can perturb a circuit when their resistances are not ideal.
Ohm’s law, resistance and nonlinear devices
For an Ohmic material under approximately unchanged physical conditions, voltage and current are proportional: V=IR. Resistance R is measured in ohms, Ω, and expresses the ratio V/I for a linear resistor. A graph with voltage on its vertical axis and current on its horizontal axis has slope R. If the axes are interchanged, the slope instead represents conductance 1/R. The area under an ordinary V–I graph is not the electrical energy of a resistor; that would require a suitable time-based energy integral.
A filament lamp’s current-voltage curve is typically nonlinear because its filament heats as the current increases. Diodes and other semiconductor components may behave asymmetrically with voltage polarity. Even an ordinary metal wire changes resistance with temperature. For these reasons the phrase ‘every conductor obeys Ohm’s law’ is false. The law describes a particular linear relationship and should always be tied to its working range. When given a graph, inspect units and slopes and distinguish a changing operating resistance from a constant material property.
Resistivity, length, area and stretching
The resistance of a uniform wire is R=ρL/A, where ρ is resistivity, L is length and A is cross-sectional area. Resistivity has SI units Ω m and depends on the material and its conditions. Two wires of equal size made from different materials may have quite different resistances because their resistivities differ. For identical material and area, resistance grows in direct proportion to length; for identical material and length, it decreases inversely with area.
Area scales as the square of cylindrical wire diameter: doubling diameter makes the area four times larger and resistance one-quarter, if L and ρ remain fixed. A stretched wire can behave differently. If a wire is extended to twice its original length while retaining volume and resistivity, its area becomes half, so its resistance becomes four times the original value. A common exam mistake is to double only L and forget the changed A. These proportionalities are appropriate for a uniform wire and not for irregular shapes or temperature-dependent changes without further analysis.
Temperature dependence and material choice
At modest temperatures many metals have approximately linear resistance dependence R_T=R_0[1+α(T−T_0)], with α a temperature coefficient. Heating increases lattice vibrations, often increasing electron scattering and resistance. This approximation works over a limited range around the specified reference temperature; α is not a universal constant. Resistivity of a metallic conductor can also be affected by composition, impurities and mechanical conditions.
Many semiconductors and negative-temperature-coefficient thermistors behave differently: heating may create enough extra carriers that resistance falls. Superconductors under suitable low-temperature, field and current conditions can have zero DC resistance, a special state rather than merely a very good ordinary metal. Selection of a wire for power delivery, a filament for a lamp, or a thermistor for sensing involves its complete electrical and thermal behaviour. Do not infer that resistivity or conductivity is determined solely by physical size; geometry affects resistance, not the intrinsic resistivity parameter.
Resistors connected in series
Resistors are in series when the same branch current passes through each successively, with no intervening branch through which charge can split. Their individual voltage drops add, so R_eq=R_1+R_2+… . For three resistors of 2 Ω, 3 Ω and 5 Ω in series the equivalent resistance is 10 Ω. At a fixed supply voltage this network draws less current than any single one of its resistors alone.
The arrangement must be determined from which nodes connect, not from how resistors are drawn on paper. Two components that appear next to one another may not be series if another connection branches at their shared node. In a series branch a higher resistance receives a larger voltage drop for the common current, according to V_i=IR_i. This is voltage division. In a real chain, an open component interrupts the whole branch; this is one reason domestic appliances are not generally wired in a single series chain.
Parallel networks and current division
Parallel resistors are connected across the same pair of circuit nodes, and therefore share the same terminal potential difference. Their currents add according to Kirchhoff’s junction rule. For ideal resistors 1/R_eq=1/R_1+1/R_2+…, and for two parallel resistors R_eq=R_1R_2/(R_1+R_2). Parallel combination of positive resistances always has an equivalent smaller than the smallest branch resistance.
When two equal resistors R are in parallel the equivalent is R/2, while series gives 2R. At fixed terminal voltage the branch with the smaller resistance carries the greater current. Household wiring normally connects appliances in parallel so switching one off does not simply interrupt all other branches. Complex networks may not permit every pair to be reduced independently. Use node tracing first and Kirchhoff’s rules for circuits with bridges or multiple interconnections that do not satisfy a simple series or parallel topology.
Electrical work, power and Joule heating
For voltage V across an element carrying steady current I, electrical power is P=VI. Under Ohmic conditions it may be rewritten as P=I²R or P=V²/R. A device rated 100 W at its operating voltage transfers about 100 joules each second. The energy transferred in time t at constant power is E=Pt. One kilowatt-hour equals 3.6 million joules and is a unit of energy, not power.
There is no universal rule that increasing resistance must increase heat output: at fixed current P=I²R rises with R, but at fixed voltage P=V²/R falls with R. Appliances, resistor heaters, fuses and transmission wires illustrate these differences. Power losses in distribution lines grow as I²R, explaining why electrical networks often use high transmission voltage to reduce current for a chosen delivered power. Always state which variable is fixed when comparing heating results, and never treat a device’s rated wattage as a constant under every possible supply condition.
Cells, emf, terminal voltage and internal resistance
Electromotive force ε is the non-electrostatic energy supplied by a source per unit charge, and its SI unit is the volt despite its name. A realistic cell can be modeled as an ideal emf in series with internal resistance r. During discharge into a resistor R, I=ε/(R+r) and terminal voltage V=ε−Ir=IR. With no delivered current the terminal voltage approaches ε; under a load some potential is dropped inside the source.
This simple model works for introductory calculations but actual battery chemistry, temperature, state of charge and current history affect the observed response. Two cells in series add emfs algebraically according to orientation and their internal resistances add for identical paths. Parallel cell connections require care when emf values differ because circulating currents can develop. The short-circuit limit ε/r can be dangerously large and should only be treated theoretically. Do not confuse emf with a mechanical force, nor assume the terminal voltage equals the nominal battery label at every current.
Kirchhoff’s laws and circuit solving
Kirchhoff’s junction rule states that total current entering a steady-state node equals total leaving it, a consequence of charge conservation. Kirchhoff’s loop rule states that the signed sum of potential differences around an ordinary lumped steady circuit loop vanishes when nonconservative induced fields are absent or appropriately accounted for. Traversing a resistor in the assumed current direction gives a drop −IR; traversing it opposite current gives +IR. Crossing a source from negative to positive terminal gives +ε in the ideal model.
Choose current directions arbitrarily and solve the resulting simultaneous equations. If a computed current is negative, its actual direction is simply opposite the assumption; it is not an impossible negative quantity. Checking one node equation and one independent loop equation is a good consistency test. In circuits influenced by time-varying magnetic flux, Faraday induction modifies how loop voltage must be handled, which is why the steady-circuit form should not be carelessly applied to every changing-field geometry. Kirchhoff methods work on circuits too complex for straightforward resistor reduction.
Wheatstone bridge and meter bridge
A Wheatstone bridge arranges four resistive arms and a detector between two intermediate junctions. At balance no detector current flows; the two junction potentials are equal. The resistance ratios then satisfy R_1/R_2=R_3/R_4 under the matching assignment of bridge arms. This null method is useful because the detector need identify only a zero, not provide a precise current measurement across its entire scale.
The meter bridge uses a uniform resistance wire with resistance proportional to its length. Its balance condition relates an unknown resistor to a known one through lengths on opposite sides of a null point. Reversing the placement of the known and unknown resistors reverses the length ratio, so a formula should always be derived from the labelled diagram. Real measurements must also contend with lead resistance, contact resistance, heating and end corrections. For competitive exams, draw the four arms, identify both intermediate nodes and write the balance relation before substituting numbers.
Electrical instruments, safety and examination strategy
An ammeter is connected in series with a branch and should have low resistance to avoid disturbing the measured current. A voltmeter goes in parallel across a component and should have high resistance so it draws little current. A galvanometer can be modified using suitable shunt or series resistors. A fuse interrupts excessive current by heating and melting, while a circuit breaker opens an overloaded or faulty circuit through a designed protective mechanism.
For rapid numerical questions, first convert all data to SI units. Next trace series and parallel sections and label current direction. Then choose V=IR, resistor reduction or Kirchhoff equations, and finally calculate power with the correct held-constant variable. In high-current circuits the source’s internal resistance and the conductors’ resistances may affect results significantly. Do not experiment with dangerous short circuits or household mains supplies to verify textbook calculations. A correct answer should satisfy both algebraic conservation and sensible power consumption.
Formula sheet
I=dQ/dtI=neAvdV=IRR=ρL/AReq=ΣR1/Req=Σ(1/R)P=VI=I²R=V²/RE=PtV=ε−IrR₁/R₂=R₃/R₄Solved numericals
A 0.5 A steady current for 180 s gives Q=0.5×180=90 C.
6 Ω and 3 Ω parallel yield 2 Ω; in series with 4 Ω total is 6 Ω.
A 12 V source across 6 Ω delivers P=V²/R=144/6=24 W.
ε=12 V, r=1 Ω, R=5 Ω gives I=12/6=2 A; terminal V=10 V.
At constant volume, doubling wire length halves area and raises R to 4R.
A balanced bridge with arms R1=2 Ω,R2=4 Ω,R3=3 Ω requires R4=6 Ω.
UPSC PYQ concept analyses
The following are paraphrased themes indexed in NDA General Ability Test Physics papers, not verbatim UPSC questions or exact official answer keys. Use the official UPSC archive to check original question wording and paper details.
Current and charge transfer
Indexed NDA Physics questions test the charge Q passing a cross-section in a given time. Convert minutes to seconds and use Q=It; divide Q by elementary charge only if a count of carriers is demanded.
Official UPSC papersEquivalent resistance of wires
An indexed NDA question considers resistance of wire segments in parallel. Find each branch resistance from length, area and resistivity; then combine by 1/Req=1/R1+1/R2.
Official UPSC papersElectrical power expressions
A previous-paper topic compares formulas for power. P=VI always represents instantaneous terminal power transfer in the simple circuit model; I²R and V²/R apply for Ohmic resistors.
Official UPSC papers20 original MCQs with answers and explanations
- volt
- ampere
- joule
- ohm
Answer and explanation
B. 1 ampere means 1 coulomb per second.
- same as electron drift
- opposite electron drift
- random
- always upwards
Answer and explanation
B. Metallic carriers are negative electrons.
- 0.6 C
- 8 C
- 15 C
- 30 C
Answer and explanation
C. Q=It=3×5=15 C.
- Ω
- Ω m
- S
- W
Answer and explanation
B. ρ=RA/L has Ω m units.
- R/2
- R
- 2R
- 4R
Answer and explanation
C. R∝L.
- 4R
- 2R
- R/2
- R/4
Answer and explanation
D. Area quadruples.
- 2 Ω
- 4 Ω
- 8 Ω
- 16 Ω
Answer and explanation
C. R_eq=4+4=8 Ω.
- 2 Ω
- 4 Ω
- 8 Ω
- 16 Ω
Answer and explanation
A. Two identical branches give R/2.
- equal
- different always
- zero
- proportional to mass
Answer and explanation
A. Each branch connects same two nodes.
- equal
- always zero
- independent randomly
- inversely proportional to time
Answer and explanation
A. A series branch has one common current.
- 2 W
- 5 W
- 10 W
- 20 W
Answer and explanation
D. P=I²R=4×5=20 W.
- 3600 J
- 3.6×10⁶ J
- 1 J
- 1000 W
Answer and explanation
B. Energy=1000 W×3600 s.
- ε+Ir
- ε−Ir
- zero
- r/ε
Answer and explanation
B. Internal drop Ir reduces terminal output.
- zero
- infinite
- 1 kΩ
- always 1 Ω
Answer and explanation
A. Ideal meter should not add branch drop.
- zero
- infinite
- negative
- equal to load
Answer and explanation
B. It draws no current.
- charge conservation
- energy conservation only
- heat capacity
- light reflection
Answer and explanation
A. Charge entering and leaving a steady node must balance.
- I/R
- R
- 1/R
- power
Answer and explanation
B. V=IR with V on vertical axis.
- 9 Ω
- 3 Ω
- 2 Ω
- 1 Ω
Answer and explanation
C. R_eq=18/9=2 Ω.
- half
- twice
- one quarter
- unchanged
Answer and explanation
B. P=V²/R.
- infinite
- battery current
- zero
- depends only on wire length
Answer and explanation
C. A balanced bridge has equal junction potentials.
