Chemistry for UPSC – Chapter 2: Atomic Structure, Quantum Numbers and Electron Configuration

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CRACKTARGET / UPSC SCIENCE MASTERCLASS

Inside the atom: from experiments to orbitals.

Understand how electrons, nuclei, spectra and quantum numbers fit together — and why Bohr’s neat circles are not the complete modern picture.

CHAPTER 02UPSC CSE · CAPF · EPFO · STATE PSCWITH SOLVED PRACTICE
8Deep-dive lessons
15Explained MCQs
100% freeRead · revise · practise
Before you begin

Why this chapter matters

UPSC-style general-science items may combine a basic discovery, an atomic-number calculation and a statement about modern electron arrangement. Learning the experiments first makes the rules of orbitals and electronic configuration more intuitive.

Exam approach

Separate experimentally established particles from models used to explain them. In every ion problem, count protons from atomic number, neutrons from mass number, and electrons from charge.

Lesson 01

The path to the modern atomic model

Dalton’s early atomic theory helped explain chemical combination, but it treated atoms as indivisible; discovery of subatomic particles and isotopes required revision. J. J. Thomson’s cathode-ray work established the electron’s charge-to-mass ratio and contributed to the discovery of the electron. Millikan’s oil-drop experiment measured the magnitude of the elementary charge.

Experiment / scientistWhat it establishedImportant limitation
Cathode rays / J. J. ThomsonNegatively charged particles (electrons); e/m ratioDid not yield a complete nuclear picture.
Oil-drop / R. A. MillikanElementary electric charge magnitudeNot a direct experiment measuring nuclear size.
Gold-foil scattering / E. Rutherford and colleaguesA tiny, concentrated, positively charged nucleus; atom mostly empty spaceClassical planetary orbits could not account for atomic stability and spectra.
Neutron discovery / J. ChadwickElectrically neutral nuclear particle, neutronNeutron is not responsible for atomic number.

Rutherford’s key evidence was that most alpha particles passed through the thin foil, but a small fraction scattered at large angles. If positive charge had been uniformly distributed throughout the atom, the latter observation would have been hard to explain.

Lesson 02

Atomic number, mass number, ions and isotopes

Atomic number (Z) equals the number of protons and defines the element. Mass number (A) counts protons plus neutrons in one nucleus. For a neutral atom, the electron count equals Z. In a cation electrons have been lost; in an anion electrons have been gained. Ordinary chemical ion formation changes electrons, not the number of protons.

Protons = Z; Neutrons = A − Z; Electrons (neutral atom) = Z
SpeciesProtonsNeutronsElectrons
²³Na atom (Z=11)111211
²³Na⁺ ion111210
³⁵Cl⁻ ion (Z=17)171818
⁴⁰Ca²⁺ ion (Z=20)202018

Isotopes have the same Z but different A (for example ¹²C and ¹⁴C). Isobars have the same A but different Z (for example ⁴⁰Ar and ⁴⁰Ca). Isotones have equal numbers of neutrons but different proton numbers. Isoelectronic species have equal numbers of electrons, even if their nuclei differ.

Two common confusions

Isotopes belong to the same element; isobars need not. Na⁺ and Ne both have 10 electrons, but are not isotopes.

Lesson 03

Why periodic-table atomic masses are often decimals

Most elements occur naturally as mixtures of isotopes. Their tabulated standard atomic weights reflect isotopic abundances and masses, so they need not be integers. A simplified numerical example uses an element with 75% of isotope mass 35 u and 25% of isotope mass 37 u.

Average mass ≈ (0.75 × 35) + (0.25 × 37) = 35.5 uThis is a deliberately rounded two-isotope illustration, not a claim that chlorine’s real abundance is precisely 75:25.

Isotope masses themselves are not always exactly equal to mass numbers expressed in u. In exam arithmetic, the problem may explicitly provide rounded mass numbers or relative abundances; use those values rather than substituting an unrelated atomic weight.

Lesson 04

Electromagnetic radiation, photons and atomic spectra

Electromagnetic radiation is described by wavelength λ, frequency ν and speed c in vacuum. Shorter wavelength means higher frequency and photon energy. Planck’s equation assigns photon energy in discrete quanta, E = hν. The visible spectrum is a relatively small part of the electromagnetic spectrum.

c = λν   |   E = hν = hc/λc ≈ 3.00 × 10⁸ m s⁻¹; h ≈ 6.626 × 10⁻³⁴ J s.
Radiation order (higher frequency → lower frequency)Useful fact
Gamma → X-ray → ultraviolet → visible → infrared → microwave → radioPhoton energy decreases from left to right; wavelength increases.
Photoelectric emissionRequires photon frequency above the metal’s threshold; increasing intensity alone cannot overcome sub-threshold frequency.

An excited atom emits radiation at characteristic wavelengths when electrons make transitions between allowed energy levels. This produces a line spectrum, rather than a continuous band covering every wavelength.

Lesson 05

Bohr’s model and hydrogen spectral series

Bohr proposed allowed stationary energy levels for the hydrogen atom. Light is absorbed or emitted when an electron changes energy level; the photon energy equals the difference between the levels. The model successfully accounts for much of the hydrogen spectrum but does not fully describe multi-electron atoms or modern orbital probability distributions.

En = −2.18 × 10⁻¹⁸ (Z²/n²) jouleFor a hydrogen-like one-electron species; n = 1, 2, 3 … and Z is nuclear charge.
Spectral seriesFinal level nRegion
Lyman1Ultraviolet
Balmer2Mostly visible (series limit in near ultraviolet)
Paschen3Infrared
Brackett4Infrared

When an electron falls from a higher energy level to a lower one, energy is emitted. When it absorbs an appropriately energetic photon, it can move to a higher level. An electron’s position is not a tiny planet following a precise circular path in the quantum-mechanical account.

Model boundary

Bohr’s fixed-radius orbits are historically important, but a modern atomic orbital is a probability-related description from quantum mechanics, not the same thing as an orbit.

Lesson 06

Quantum numbers and the meaning of orbitals

Quantum mechanics describes electron states with four quantum numbers. The principal number n gives shell and energy/size information; the azimuthal number l specifies subshell type; the magnetic number ml labels orbitals within a subshell; and spin ms distinguishes two allowed spin projections.

NumberAllowed valuesWhat to remember
n1, 2, 3, …Principal shell; maximum electrons per shell = 2n².
l0 to n−10=s, 1=p, 2=d, 3=f.
mₗ−l through +lNumber of orbitals in a subshell = 2l+1.
mₛ+½ or −½Each orbital can hold at most two electrons with opposite spins.
s subshell

1 orbital; maximum 2 electrons.

p subshell

3 orbitals; maximum 6 electrons.

d subshell

5 orbitals; maximum 10 electrons.

f subshell

7 orbitals; maximum 14 electrons.

Why a 2d subshell cannot exist

For n = 2, l may be 0 or 1 only. A d subshell requires l = 2 and therefore n ≥ 3.

Lesson 07

Aufbau principle, Pauli exclusion and Hund’s rule

Electron configuration assigns electrons to orbitals. In the Aufbau scheme, lower-energy orbitals fill first for the ground state, with the (n+l) guideline helping determine the usual order. Pauli exclusion prevents two electrons in one atom from sharing all four quantum numbers. Hund’s rule directs electrons to occupy degenerate orbitals singly with parallel spins before pairing, for a typical ground-state arrangement.

Usual early filling: 1s → 2s → 2p → 3s → 3p → 4s → 3d → 4pThe 4s subshell fills before 3d in the usual neutral-atom buildup, but 4s electrons are commonly removed first when many transition-metal cations form.
ElementZGround-state electron configuration
Carbon61s² 2s² 2p²
Neon101s² 2s² 2p⁶
Sodium111s² 2s² 2p⁶ 3s¹
Chlorine171s² 2s² 2p⁶ 3s² 3p⁵
Argon181s² 2s² 2p⁶ 3s² 3p⁶

Some transition-metal neutral atoms depart from a simple mechanical filling prediction: chromium is approximately [Ar] 3d⁵4s¹ and copper [Ar] 3d¹⁰4s¹. These special configurations are frequently used to test whether candidates merely memorised a sequence.

Lesson 08

Two solved methods for particle-count and orbital questions

Example A: Count subatomic particles

For ²⁷Al³⁺, aluminium has Z = 13 and A = 27.
Protons = 13; neutrons = 27 − 13 = 14.
The 3+ charge means three electrons lost relative to the neutral atom, so electrons = 13 − 3 = 10.

Example B: Capacity of the n = 3 shell

For n = 3, allowed l values are 0 (3s), 1 (3p) and 2 (3d). Together there are 1 + 3 + 5 = 9 orbitals, allowing up to 18 electrons. This is the shell’s maximum capacity, not a claim that every atom fills its third shell completely before any fourth-shell orbital begins to fill.

Think in three columns

Z determines identity; A−Z gives neutrons; charge adjusts electron count. For orbitals, write allowed n and l before assigning capacity.

Last-minute revision

One-minute recall sheet

  • Z = number of protons; A = protons + neutrons; ion charge changes electron number.
  • Isotopes: same Z, different A. Isobars: same A, different Z.
  • Photon energy E = hν; shorter wavelength means greater photon energy.
  • Bohr model explains hydrogen-like spectra; a modern orbital is not a fixed trajectory.
  • For shell n, l = 0 to n−1; orbitals in a subshell = 2l+1; capacity = 2(2l+1).
  • Pauli: two electrons per orbital with opposite spins; Hund: single occupation before pairing in degenerate orbitals.
  • Neutral Cr and Cu exhibit familiar configurations [Ar]3d⁵4s¹ and [Ar]3d¹⁰4s¹.
Common UPSC trap

The 2n² shell formula gives maximum capacity, not the simple chronological filling pattern in every element. Do not treat a Rutherford orbit, a Bohr orbit and a quantum orbital as synonyms.

Check application, not memory alone

UPSC-style practice — 15 explained questions

These are original practice questions, not claims of verbatim UPSC previous-year questions. Attempt each before opening the answer. Questions are single-correct unless specified.

1Which experiment gave particularly strong evidence for a small, dense atomic nucleus?
A. Millikan oil-drop experiment
B. Rutherford gold-foil scattering
C. Brownian motion observations
D. Electrolysis of water
Show correct answer and explanation

Answer: B. Large-angle alpha scattering required a concentrated positive centre, not a diffuse positive sphere.

2For ²³Na⁺ (Z = 11), the numbers of protons, neutrons and electrons are:
A. 11, 12, 10
B. 11, 11, 12
C. 10, 12, 11
D. 12, 11, 10
Show correct answer and explanation

Answer: A. Protons=11, neutrons=23−11=12, electrons=11−1=10.

3Two atoms are isotopes when they have:
A. Same mass number and different proton number
B. Same neutron number and mass number
C. Same proton number and different neutron number
D. Same electrons but different elements
Show correct answer and explanation

Answer: C. Same Z defines the element; isotope variation is in neutron number and thus usually A.

4Which pair is isoelectronic?
A. Na and Ne
B. Na⁺ and Ne
C. Cl and Ne
D. O and F
Show correct answer and explanation

Answer: B. Na⁺ has 10 electrons and neutral neon also has 10.

5An isotope of mass 35 u has 75% abundance and another of 37 u has 25%. Approximate weighted mass:
A. 35.0 u
B. 35.25 u
C. 35.5 u
D. 36.0 u
Show correct answer and explanation

Answer: C. 0.75×35 + 0.25×37 = 35.5 u.

6If wavelength is halved in vacuum, photon energy becomes:
A. Half
B. Twice
C. Four times
D. Unchanged
Show correct answer and explanation

Answer: B. Photon energy E=hc/λ, so it is inversely proportional to λ.

7Which spectral series consists of hydrogen transitions ending at n = 1?
A. Balmer
B. Paschen
C. Brackett
D. Lyman
Show correct answer and explanation

Answer: D. The Lyman series ends at n=1 and lies in ultraviolet wavelengths.

8According to the quantum-number rules, which subshell is impossible?
A. 2p
B. 3d
C. 2d
D. 4f
Show correct answer and explanation

Answer: C. A 2d subshell would need n=2, l=2, but for n=2 only l=0,1 are possible.

9How many orbitals are present in a d subshell?
A. 3
B. 5
C. 7
D. 10
Show correct answer and explanation

Answer: B. For l=2, 2l+1=5 orbitals; each holds at most 2 electrons.

10Maximum number of electrons in an isolated p subshell is:
A. 2
B. 3
C. 6
D. 8
Show correct answer and explanation

Answer: C. There are 3 p orbitals and 2 electron slots in each, yielding 6.

11Which principle forbids two electrons in the same atom from having identical four quantum numbers?
A. Aufbau principle
B. Hund’s rule
C. Avogadro’s law
D. Pauli exclusion principle
Show correct answer and explanation

Answer: D. Pauli exclusion concerns uniqueness of the full quantum state.

12The ground-state electron configuration of sodium (Z = 11) ends with:
A. 2p⁷
B. 3s¹
C. 3p¹
D. 3s²
Show correct answer and explanation

Answer: B. After neon core 1s²2s²2p⁶, the 11th electron occupies 3s.

13How many electrons are in ²⁷Al³⁺, where Z = 13?
A. 10
B. 13
C. 14
D. 16
Show correct answer and explanation

Answer: A. The 3+ cation has lost three electrons from the neutral 13-electron atom.

14An electron transitioning from n = 3 to n = 2 in hydrogen:
A. Absorbs a photon
B. Emits a photon
C. Changes the proton number
D. Creates a neutron
Show correct answer and explanation

Answer: B. Moving to a lower-energy level releases a photon; n=3→2 is a Balmer transition.

15Which familiar configuration is correct for neutral copper (Z = 29)?
A. [Ar] 3d⁹4s²
B. [Ar] 3d⁸4s³
C. [Ar] 3d¹⁰4s¹
D. [Ar] 3d¹¹
Show correct answer and explanation

Answer: C. Neutral Cu has the experimentally favoured [Ar]3d¹⁰4s¹ arrangement.

Read further

Primary references and revision links

Chapter explanations and practice questions are prepared for general-science revision. Topic coverage and depth differ by examination and official syllabus.

Study pathway

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