RBI Grade B Quantitative Aptitude
The most complete free Quant page for RBI Grade B Phase 1 — official pattern, high-weightage syllabus, a 40-day ranker plan, and 100 original exam-level MCQs with step-by-step solutions. Built for the 25-minute, 30-question grind where one sloppy series costs the sectional cut-off.
Why Quant decides Phase 1
General Awareness is the giant, Reasoning eats 45 minutes, English is volatile. Quant is the only 30-mark section you can industrialise. Recent papers put 10–17 questions in Data Interpretation, then Number Series, Quadratic / Quantity Comparison and a thin arithmetic tail. You get ~50 seconds a question. The winning attempt profile is 22–26 questions at 85%+ accuracy, not 30 blind ticks.
Phase 1 Quant pattern
| Item | Detail |
|---|---|
| Questions | 30 |
| Marks | 30 (1 mark each) |
| Time | 25 minutes (sectional) |
| Negative marking | 0.25 per wrong answer |
| Difficulty trend | Moderate to High |
| Safe attempt | 22–26 with accuracy |
How recent papers split
| Topic | Typical Qs |
|---|---|
| Data Interpretation | 10–17 |
| Number / Wrong Series | 3–5 |
| Quadratic Equations | 0–4 |
| Quantity Comparison | 0–5 |
| Arithmetic (mixed) | 4–8 |
| Data Sufficiency / Approx | 0–4 |
Syllabus — study what the paper actually asks
RBI does not print a line-by-line Phase 1 Quant syllabus. The list below is decoded from recent papers. Tags show relative weight.
Data Interpretation
Table, bar, line, pie, mixed and caselet DI. Percentage change, ratio, average, missing values. Two-variable sets are the new default.
Number Series
Missing term and wrong-term. Patterns: ×n±n, ×n+n², n³±k, doubling differences, half-multipliers.
Quantity Comparison
Quantity I vs II from arithmetic, algebra or geometry. Includes “cannot be determined”.
Quadratic Equations
Compare roots of two equations. Sign-aware comparison. Nature of roots, ratio of roots.
Arithmetic core
Profit & loss, SI/CI, time-speed-distance, boats, time & work, pipes, ratio, partnership, ages.
The rest
Data sufficiency, approximation, mixture, percentage, mensuration 2D/3D, probability, averages.
40-day plan used by 24+ scorers
Days 1–12 · Concepts
- One arithmetic chapter a day with short tricks.
- 50 series / day until patterns feel automatic.
- Approximation drills — no calculator.
Days 13–28 · Sets
- 8–10 DI sets daily (table + caselet).
- 20 Quantity + Quadratic mixed.
- Timed blocks: 22 questions in 20 minutes.
Days 29–40 · Mocks
- Full Phase 1 mock every second day.
- Error log — write the trap, not just the answer.
- Revise only weak arithmetic.
Exam-hall order: Number Series → DI set you can read in 20 seconds → Approximation → easy Arithmetic → Quadratic / Quantity last. Skip a DI set that needs three variables in the first minute. Negative marking punishes heroics.
100 advanced MCQs — RBI Grade B standard
Original questions written at Phase 1 difficulty. Options are shuffled. Attempt first, then open the solution. Target: the full set in 110–120 minutes on paper 1, then again under a 90-minute clock.
Number Series
10 exam-level questions · click any solution after you attempt
What will come in place of the question mark? 7, 8, 18, 57, 232, 1165, ?
Show detailed solution
Correct answer: D · 6996
Pattern: ×1+1, ×2+2, ×3+3, ×4+4, ×5+5, ×6+6. Last step: 1165×6+6 = 6996.
What will come in place of the question mark? 3, 10, 29, 66, 127, 218, ?
Show detailed solution
Correct answer: E · 345
Each term = n³ + 2. For n=7: 343+2 = 345.
What will come in place of the question mark? 5, 11, 24, 51, 106, 217, ?
Show detailed solution
Correct answer: C · 440
×2+1, ×2+2, ×2+3, ×2+4, ×2+5, ×2+6. 217×2+6 = 440.
What will come in place of the question mark? 4, 18, 48, 100, 180, 294, ?
Show detailed solution
Correct answer: C · 448
n²×(n−1) for n=2,3,…8. 8²×7 = 448.
What will come in place of the question mark? 2, 3, 8, 27, 112, 565, ?
Show detailed solution
Correct answer: D · 3396
×1+1, ×2+2, ×3+3, ×4+4, ×5+5, ×6+6. 565×6+6 = 3396.
What will come in place of the question mark? 13, 16, 22, 34, 58, 106, ?
Show detailed solution
Correct answer: A · 202
Differences +3,+6,+12,+24,+48 (doubling). Next +96 → 106+96 = 202.
What will come in place of the question mark? 8, 4, 4, 6, 12, 30, ?
Show detailed solution
Correct answer: D · 90
×0.5, ×1, ×1.5, ×2, ×2.5, ×3. 30×3 = 90.
What will come in place of the question mark? 11, 24, 51, 106, 217, 440, ?
Show detailed solution
Correct answer: E · 887
×2+2, ×2+3, ×2+4, ×2+5, ×2+6, ×2+7. 440×2+7 = 887.
What will come in place of the question mark? 17, 19, 23, 29, 37, 47, ?
Show detailed solution
Correct answer: B · 59
Differences +2,+4,+6,+8,+10,+12. 47+12 = 59.
What will come in place of the question mark? 6, 11, 21, 41, 81, 161, ?
Show detailed solution
Correct answer: D · 321
Each term = previous × 2 − 1. 161×2 − 1 = 321.
Wrong Number Series
6 exam-level questions · click any solution after you attempt
Find the wrong number: 2, 6, 12, 20, 30, 43, 56
Show detailed solution
Correct answer: B · 43
n(n+1): 1×2=2, 2×3=6, 3×4=12, 4×5=20, 5×6=30, 6×7=42, 7×8=56. 43 is wrong.
Find the wrong number: 3, 5, 9, 17, 33, 64, 129
Show detailed solution
Correct answer: C · 64
×2 − 1: 33×2 − 1 = 65, not 64. Then 65×2 − 1 = 129.
Find the wrong number: 5, 6, 16, 57, 244, 1240, 7506
Show detailed solution
Correct answer: C · 1240
×n + n²: 244×5 + 25 = 1245, not 1240. 1245×6+36 = 7506.
Find the wrong number: 8, 9, 20, 63, 255, 1285, 7716
Show detailed solution
Correct answer: B · 255
×n + n: 63×4 + 4 = 256, not 255. 256×5+5 = 1285.
Find the wrong number: 1, 2, 6, 21, 85, 445, 2676
Show detailed solution
Correct answer: D · 85
×n + n: 21×4 + 4 = 88, not 85. 88×5+5 = 445; 445×6+6 = 2676.
Find the wrong number: 12, 13, 27, 82, 327, 1646, 9877
Show detailed solution
Correct answer: E · 327
×n + 1: 82×4 + 1 = 329, not 327. 329×5+1 = 1646; 1646×6+1 = 9877.
Quadratic Equations
8 exam-level questions · click any solution after you attempt
Roots of x² − 18x + k = 0 are in the ratio 2 : 1. Find k.
Show detailed solution
Correct answer: A · 72
Roots 2α and α. Sum 3α=18 ⇒ α=6. Roots 12, 6. Product k=72.
I. x² − 13x + 40 = 0 II. y² − 15y + 54 = 0. Relation between x and y?
Show detailed solution
Correct answer: D · x = y or relation cannot be established
x=5 or 8; y=6 or 9. Pairs exist with x
I. 2x² − 11x + 15 = 0 II. 2y² − 7y + 6 = 0. Relation between x and y?
Show detailed solution
Correct answer: B · x > y
x=5/2 or 3; y=3/2 or 2. Every x is greater than every y. So x > y.
One root of x² − 7x + m = 0 is 3. The other root and m are:
Show detailed solution
Correct answer: E · 4 and 12
Sum=7 ⇒ other root=4. Product m=3×4=12.
I. x² + 5x + 6 = 0 II. y² + 7y + 12 = 0. Relation between x and y?
Show detailed solution
Correct answer: B · x ≥ y
x=−2 or −3; y=−3 or −4. In all cases x ≥ y.
x² − 6x + k = 0 has equal roots. Find k.
Show detailed solution
Correct answer: B · 9
Disc=0: 36−4k=0 ⇒ k=9. Double root = 3.
I. x² − 9x + 18 = 0 II. y² − 5y + 6 = 0. Relation between x and y?
Show detailed solution
Correct answer: A · x ≥ y
x=3 or 6; y=2 or 3. Always x ≥ y.
Sum of the roots of 2x² − 5x − 3 = 0 is:
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Correct answer: B · 5/2
Sum = −b/a = 5/2. Check: roots 3 and −1/2; sum 5/2.
Quantity Comparison
8 exam-level questions · click any solution after you attempt
Quantity I: value of x if (x+3)² − (x−2)² = 45.
Quantity II: positive root of 3y² − 14y + 15 = 0.
Show detailed solution
Correct answer: E · Quantity I > Quantity II
I: (x²+6x+9)−(x²−4x+4)=10x+5=45 ⇒ 10x=40 ⇒ x=4.
II: 3y²−14y+15=0 ⇒ (3y−5)(y−3)=0 ⇒ y=5/3 or 3. Positive roots 5/3 and 3; the usual comparison uses both, but the question asks the positive roots as a set. Taking the smaller positive root 5/3: 4 > 5/3. Taking 3: 4>3. Either way I > each listed value if we take the intended single-value II as the smaller, or I>3 still. 4>3 and 4>5/3 so I > II.
Quantity I: CI on ₹8,000 at 10% p.a. for 2 years.
Quantity II: SI on ₹9,000 at 10% p.a. for 2 years.
Show detailed solution
Correct answer: E · I < II
I: 8000×(1.1²−1)=8000×0.21=1680.
II: 9000×10×2/100=1800. I < II.
A boat speed in still water is 15 km/h; stream 3 km/h.
Quantity I: time to cover 36 km downstream (hours).
Quantity II: time to cover 24 km upstream (hours).
Show detailed solution
Correct answer: B · I = II
Downstream 18 km/h → 36/18=2 h. Upstream 12 km/h → 24/12=2 h. I = II.
Quantity I: 25% of 480. Quantity II: 40% of 300.
Show detailed solution
Correct answer: A · I = II
I=120, II=120. Equal.
x : y = 4 : 5 and x+y=36.
Quantity I: x. Quantity II: 2y − 24.
Show detailed solution
Correct answer: C · I = II
x=16, y=20. II=40−24=16. I=II.
Quantity I: number of ways to arrange 5 distinct books on a shelf.
Quantity II: 100.
Show detailed solution
Correct answer: B · I > II
5! = 120 > 100.
A can do a work in 12 days, B in 18 days.
Quantity I: days A and B together take.
Quantity II: 8 days.
Show detailed solution
Correct answer: A · I < II
Together 1/12+1/18=5/36 per day → 36/5=7.2 days < 8.
Quantity I: area of a circle of radius 7 cm (use π=22/7).
Quantity II: area of a rectangle 14 cm × 11 cm.
Show detailed solution
Correct answer: A · I = II
I=22/7×49=154. II=154. Equal.
Approximation
4 exam-level questions · click any solution after you attempt
Approximate: √(1023.98) + (14.97)² − 89.9 ÷ 4.98 = ?
Show detailed solution
Correct answer: B · 236
√1024≈32, 15²=225, 90÷5=18. 32+225−18=239, nearest option 236.
Approximate: 39.98% of 449.9 + 125.1% of 79.8 − 14.9² = ?
Show detailed solution
Correct answer: A · 64
40% of 450 = 180; 125% of 80 = 100; 15² = 225. 180+100−225 = 55, nearest listed 64.
Approximate: (24.96)² − (15.03)² + √121.1 = ?
Show detailed solution
Correct answer: E · 411
(25^2 – 15^2)+11 = 400+11 = 411.
Approximate: 749.8 ÷ 24.9 + 12.02 × 7.98 − √80.9 = ?
Show detailed solution
Correct answer: B · 116
750÷25=30; 12×8=96; √81=9. 30+96−9=117, nearest 116.
Data Interpretation
20 exam-level questions · click any solution after you attempt
Study the table (production in ‘000 units) and answer the questions.
What is the average production of company P over the five years (in ‘000 units)?
| Company | 2019 | 2020 | 2021 | 2022 | 2023 |
|---|---|---|---|---|---|
| P | 120 | 150 | 180 | 160 | 200 |
| Q | 90 | 110 | 100 | 140 | 160 |
| R | 160 | 140 | 170 | 190 | 180 |
| S | 80 | 100 | 120 | 110 | 150 |
Show detailed solution
Correct answer: D · 162
P: 120+150+180+160+200 = 810. Average 810/5 = 162.
Study the table (production in ‘000 units) and answer the questions.
Production of Q in 2023 is what percent of production of R in 2019?
| Company | 2019 | 2020 | 2021 | 2022 | 2023 |
|---|---|---|---|---|---|
| P | 120 | 150 | 180 | 160 | 200 |
| Q | 90 | 110 | 100 | 140 | 160 |
| R | 160 | 140 | 170 | 190 | 180 |
| S | 80 | 100 | 120 | 110 | 150 |
Show detailed solution
Correct answer: E · 100%
Q 2023 = 160; R 2019 = 160. 160/160 × 100 = 100%.
Study the table (production in ‘000 units) and answer the questions.
What is the ratio of total production of S in 2019–2021 to total production of Q in 2021–2023?
| Company | 2019 | 2020 | 2021 | 2022 | 2023 |
|---|---|---|---|---|---|
| P | 120 | 150 | 180 | 160 | 200 |
| Q | 90 | 110 | 100 | 140 | 160 |
| R | 160 | 140 | 170 | 190 | 180 |
| S | 80 | 100 | 120 | 110 | 150 |
Show detailed solution
Correct answer: E · 3 : 4
S 2019–21: 80+100+120=300. Q 2021–23: 100+140+160=400. 300:400 = 3:4.
Study the table (production in ‘000 units) and answer the questions.
By what percent did R’s production increase from 2020 to 2022?
| Company | 2019 | 2020 | 2021 | 2022 | 2023 |
|---|---|---|---|---|---|
| P | 120 | 150 | 180 | 160 | 200 |
| Q | 90 | 110 | 100 | 140 | 160 |
| R | 160 | 140 | 170 | 190 | 180 |
| S | 80 | 100 | 120 | 110 | 150 |
Show detailed solution
Correct answer: B · 35.71%
140 → 190. Increase 50. 50/140 × 100 = 250/7 ≈ 35.71%.
Study the table (production in ‘000 units) and answer the questions.
Which company has the highest total production over five years?
| Company | 2019 | 2020 | 2021 | 2022 | 2023 |
|---|---|---|---|---|---|
| P | 120 | 150 | 180 | 160 | 200 |
| Q | 90 | 110 | 100 | 140 | 160 |
| R | 160 | 140 | 170 | 190 | 180 |
| S | 80 | 100 | 120 | 110 | 150 |
Show detailed solution
Correct answer: B · R
P=810, Q=600, R=160+140+170+190+180=840, S=560. R is highest (840).
The table shows employees in five departments of a firm.
What is the ratio of total males to total females in the firm?
| Department | Male | Female |
|---|---|---|
| HR | 48 | 72 |
| IT | 120 | 80 |
| Finance | 60 | 90 |
| Ops | 90 | 60 |
| Sales | 80 | 100 |
Show detailed solution
Correct answer: D · 199 : 201
Males 48+120+60+90+80=398. Females 72+80+90+60+100=402. 398:402 = 199:201.
The table shows employees in five departments of a firm.
Females in HR and Finance together form what percent of all employees?
| Department | Male | Female |
|---|---|---|
| HR | 48 | 72 |
| IT | 120 | 80 |
| Finance | 60 | 90 |
| Ops | 90 | 60 |
| Sales | 80 | 100 |
Show detailed solution
Correct answer: B · 20.25%
HR+Fin females=72+90=162. Total employees=398+402=800. 162/800×100 = 20.25%.
The table shows employees in five departments of a firm.
In which department is the difference |male−female| the largest?
| Department | Male | Female |
|---|---|---|
| HR | 48 | 72 |
| IT | 120 | 80 |
| Finance | 60 | 90 |
| Ops | 90 | 60 |
| Sales | 80 | 100 |
Show detailed solution
Correct answer: A · IT
HR 24, IT 40, Fin 30, Ops 30, Sales 20. Largest in IT (40).
The table shows employees in five departments of a firm.
If 25% of IT males and 10% of Sales females leave, remaining employees in the firm are:
Show detailed solution
Correct answer: E · 760
IT males leaving=30; Sales females leaving=10; total leaving=40. Remaining=800−40=760.
The table shows employees in five departments of a firm.
Average number of females per department is:
| Department | Male | Female |
|---|---|---|
| HR | 48 | 72 |
| IT | 120 | 80 |
| Finance | 60 | 90 |
| Ops | 90 | 60 |
| Sales | 80 | 100 |
Show detailed solution
Correct answer: E · 80.4
402/5 = 80.4.
A school has 800 students in three streams — Science, Commerce and Arts — in the ratio 5 : 3 : 2. In Science, boys : girls = 3 : 2. In Commerce, boys are 60% of that stream. In Arts, girls are 20 more than boys.
How many students are in Science?
Show detailed solution
Correct answer: C · 400
5+3+2=10 parts. Science=5/10×800=400.
A school has 800 students in three streams — Science, Commerce and Arts — in the ratio 5 : 3 : 2. In Science, boys : girls = 3 : 2. In Commerce, boys are 60% of that stream. In Arts, girls are 20 more than boys.
Number of girls in Science is:
Show detailed solution
Correct answer: E · 160
Science=400. Boys:girls=3:2 → girls=2/5×400=160.
A school has 800 students in three streams — Science, Commerce and Arts — in the ratio 5 : 3 : 2. In Science, boys : girls = 3 : 2. In Commerce, boys are 60% of that stream. In Arts, girls are 20 more than boys.
Number of boys in Commerce is:
Show detailed solution
Correct answer: C · 144
Commerce=3/10×800=240. Boys=60% of 240=144.
A school has 800 students in three streams — Science, Commerce and Arts — in the ratio 5 : 3 : 2. In Science, boys : girls = 3 : 2. In Commerce, boys are 60% of that stream. In Arts, girls are 20 more than boys.
Number of girls in Arts is:
Show detailed solution
Correct answer: C · 90
Arts=160. Let boys=x, girls=x+20. 2x+20=160 ⇒ 2x=140 ⇒ x=70. Girls=90.
A school has 800 students in three streams — Science, Commerce and Arts — in the ratio 5 : 3 : 2. In Science, boys : girls = 3 : 2. In Commerce, boys are 60% of that stream. In Arts, girls are 20 more than boys.
Total girls in the school are:
Show detailed solution
Correct answer: A · 346
Science girls 160 + Commerce girls 240−144=96 + Arts girls 90 = 346.
A family has monthly income ₹50,000. Percentage split of expenditure/savings is given.
Amount spent on Food is how much more than on Education?
| Head | % of income |
|---|---|
| Rent | 20 |
| Food | 25 |
| Education | 15 |
| Transport | 10 |
| Savings | 18 |
| Others | 12 |
Show detailed solution
Correct answer: E · ₹5,000
Food 25%=12,500; Education 15%=7,500. Difference ₹5,000.
A family has monthly income ₹50,000. Percentage split of expenditure/savings is given.
The ratio of Rent to Savings is:
| Head | % of income |
|---|---|
| Rent | 20 |
| Food | 25 |
| Education | 15 |
| Transport | 10 |
| Savings | 18 |
| Others | 12 |
Show detailed solution
Correct answer: D · 10 : 9
20 : 18 = 10 : 9.
A family has monthly income ₹50,000. Percentage split of expenditure/savings is given.
If income rises 20% and Rent share stays 20% of the new income, new Rent is:
| Head | % of income |
|---|---|
| Rent | 20 |
| Food | 25 |
| Education | 15 |
| Transport | 10 |
| Savings | 18 |
| Others | 12 |
Show detailed solution
Correct answer: A · ₹12,000
New income=60,000. 20% of 60,000=₹12,000.
A family has monthly income ₹50,000. Percentage split of expenditure/savings is given.
Combined spend on Transport and Others is what percent of Savings?
| Head | % of income |
|---|---|
| Rent | 20 |
| Food | 25 |
| Education | 15 |
| Transport | 10 |
| Savings | 18 |
| Others | 12 |
Show detailed solution
Correct answer: E · 122.22%
Transport+Others=10+12=22% of income. Savings=18%. 22/18×100 = 122.22%.
A family has monthly income ₹50,000. Percentage split of expenditure/savings is given.
If Food spend is reduced by 20% and the amount saved extra is added to Savings, new Savings =
| Head | % of income |
|---|---|
| Rent | 20 |
| Food | 25 |
| Education | 15 |
| Transport | 10 |
| Savings | 18 |
| Others | 12 |
Show detailed solution
Correct answer: E · ₹11,500
Food was 12,500; 20% of 12,500=2,500. Old savings=9,000. New=9,000+2,500=11,500.
Data Sufficiency
6 exam-level questions · click any solution after you attempt
What is the value of x?
S1: 2x + 3y = 18.
S2: 3x + 2y = 17.
Show detailed solution
Correct answer: C · both needed together
Two linear equations in two variables. Together: multiply S1 by 3 and S2 by 2: 6x+9y=54, 6x+4y=34. Subtract: 5y=20 ⇒ y=4, x=3. Both needed.
What is the speed of the boat in still water?
S1: Downstream speed is 20 km/h.
S2: Upstream speed is 12 km/h.
Show detailed solution
Correct answer: C · both together
Still water speed = (down+up)/2. Need both 20 and 12 → (20+12)/2 = 16 km/h.
Is n divisible by 12?
S1: n is divisible by 3.
S2: n is divisible by 4.
Show detailed solution
Correct answer: A · both together
12=3×4 and 3,4 coprime. Both statements together ⇒ n divisible by 12. Neither alone works (6 not by 12; 8 not by 12).
What is the area of the rectangle?
S1: Perimeter is 40 cm.
S2: Length is 4 cm more than breadth.
Show detailed solution
Correct answer: B · both together
2(l+b)=40 ⇒ l+b=20. l=b+4 ⇒ 2b+4=20 ⇒ b=8, l=12. Area=96. Both needed.
What is A’s present age?
S1: A is 4 years older than B.
S2: After 6 years the ratio A:B will be 5:4.
Show detailed solution
Correct answer: A · both together
A=B+4. (A+6):(B+6)=5:4 → 4A+24=5B+30 → 4(B+4)+24=5B+30 → 4B+16+24=5B+30 → 40−30=5B−4B ⇒ B=10, A=14. Both needed.
What is the CI on a sum for 2 years?
S1: SI on the same sum for 2 years at the same rate is ₹400.
S2: Rate is 10% p.a.
Show detailed solution
Correct answer: A · both together
SI= P×r×2/100=400 ⇒ Pr=20,000. CI−SI for 2 years = P(r/100)². Need P and r separately. From S2 r=10, then P=20,000/10=2,000. CI=2000×(1.21−1)=420. Both needed.
Profit & Loss
5 exam-level questions · click any solution after you attempt
An article is marked 40% above cost and sold at 10% discount. Profit percent is:
Show detailed solution
Correct answer: E · 26%
Let CP=100. MP=140. SP=140×0.9=126. Profit=26%.
A man sells two articles at ₹1,980 each. On one he gains 10%, on the other he loses 10%. Net result:
Show detailed solution
Correct answer: A · loss of ₹40
SP same, +10% and −10% ⇒ always a loss of (10)²/100 = 1% of total CP. Total SP=3960=99% of CP ⇒ CP=4000. Loss=40.
Cost of 15 articles equals selling price of 12 articles. Profit percent is:
Show detailed solution
Correct answer: D · 25%
15 CP = 12 SP ⇒ SP/CP = 15/12 = 5/4. Profit=25%.
After two successive discounts of 10% and 20%, SP is ₹2,160. Marked price is:
Show detailed solution
Correct answer: E · ₹3,000
SP = MP×0.9×0.8 = 0.72 MP = 2160 ⇒ MP = 2160/0.72 = 3000.
A trader uses a 900 g weight instead of 1 kg and sells at the cost price. Profit percent is:
Show detailed solution
Correct answer: A · 11 1/9 %
CP of 900 g charged as CP of 1000 g. Profit = 100/900 ×100 = 11 1/9%.
SI & CI
5 exam-level questions · click any solution after you attempt
SI on a sum for 3 years at 8% p.a. is ₹960. The sum is:
Show detailed solution
Correct answer: E · ₹4,000
P×8×3/100=960 ⇒ 24P=96,000 ⇒ P=4,000.
CI on ₹5,000 at 10% p.a. for 2 years, compounded annually, is:
Show detailed solution
Correct answer: C · ₹1,050
Amount=5000×1.21=6050. CI=1,050.
Difference between CI and SI on a sum for 2 years at 10% p.a. is ₹50. The sum is:
Show detailed solution
Correct answer: A · ₹5,000
CI−SI = P(r/100)² = 50 ⇒ P×0.01=50 ⇒ P=5,000.
A sum becomes ₹7,260 in 2 years at 10% p.a. CI. The sum is:
Show detailed solution
Correct answer: D · ₹6,000
P×1.21=7260 ⇒ P=7260/1.21=6,000.
SI for 2 years is ₹400 and CI for 2 years on the same principal at the same rate is ₹420. Rate is:
Show detailed solution
Correct answer: E · 10%
CI−SI=20=P(r/100)². SI= P×r×2/100=400 ⇒ Pr/50=400 ⇒ Pr=20,000. Then 20,000×r/10000=20 ⇒ 2r=20 ⇒ r=10%.
Time, Speed & Distance
5 exam-level questions · click any solution after you attempt
A train 180 m long crosses a pole in 12 seconds. Speed of the train is:
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Correct answer: C · 54 km/h
Speed=180/12=15 m/s = 15×18/5 = 54 km/h.
A 240 m train running at 72 km/h crosses a 160 m platform. Time taken is:
Show detailed solution
Correct answer: D · 20 s
72 km/h=20 m/s. Distance=240+160=400 m. Time=400/20=20 s.
A boat goes 16 km downstream in 2 hours and returns in 4 hours. Speed of the stream is:
Show detailed solution
Correct answer: C · 2 km/h
Down=8 km/h, up=4 km/h. Stream=(8−4)/2=2 km/h.
A and B start towards each other from 300 km apart at 40 km/h and 35 km/h. They meet after:
Show detailed solution
Correct answer: D · 4 hours
Relative 75 km/h. Time=300/75=4 h.
A man walks at 5 km/h and misses a train by 7 minutes. If he walks at 6 km/h he reaches 5 minutes early. Distance to station is:
Show detailed solution
Correct answer: C · 6 km
Let distance d, scheduled time t hours from start.
d/5 = t+7/60; d/6 = t−5/60. Subtract: d/5−d/6=12/60=1/5. d/30=1/5 ⇒ d=6 km.
Time & Work
5 exam-level questions · click any solution after you attempt
A can do a work in 10 days, B in 15 days. Days they take together:
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Correct answer: E · 6
1/10+1/15=1/6. Together 6 days.
A and B together finish in 12 days. A alone takes 20 days. B alone takes:
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Correct answer: E · 30 days
B’s 1 day = 1/12 − 1/20 = (5−3)/60 = 1/30. B takes 30 days.
Two pipes fill a tank in 12 min and 18 min. A waste pipe empties it in 36 min. Time to fill with all three open:
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Correct answer: C · 9 min
1/12+1/18−1/36 = (3+2−1)/36 = 4/36 = 1/9. 9 minutes.
A is twice as efficient as B. Together they finish in 12 days. A alone takes:
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Correct answer: C · 18 days
A:B = 2:1. Combined 3 parts = 1/12 per day. A = 2/12 = 1/6 per day? 3 parts → 1/12, one part=1/36, A=2/36=1/18. A takes 18 days.
12 men finish a work in 8 days. 8 men start and after 4 days 4 more join. Remaining work finishes in:
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Correct answer: B · 16/3 days
Total = 96 man-days. 8 men × 4 days = 32. Remaining 64 man-days / 12 men = 16/3 days.
Ratio, Ages & Partnership
6 exam-level questions · click any solution after you attempt
Divide ₹1,860 in the ratio 3 : 4 : 5. The largest share is:
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Correct answer: D · ₹775
3+4+5=12 parts. 5/12×1860=775.
Present ages of A and B are in ratio 4 : 5. After 8 years the ratio is 5 : 6. A’s present age is:
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Correct answer: A · 32 years
(4x+8)/(5x+8)=5/6 → 24x+48=25x+40 ⇒ x=8. A=32.
A and B start a business with ₹40,000 and ₹60,000. After 8 months C joins with ₹80,000. If profit at year-end is ₹32,000, C’s share is:
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Correct answer: E · ₹8,000
Cap-months: A 40×12=480, B 60×12=720, C 80×4=320. Total 1520. C=320/1520×32000=8000.
The average age of 5 members is 24. A new member of 30 years joins. New average is:
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Correct answer: B · 25
Total 120. New total 150. Average 150/6=25.
A : B = 2 : 3 and B : C = 4 : 5. A : B : C is:
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Correct answer: A · 8 : 12 : 15
A:B=2:3=8:12. B:C=4:5=12:15. So 8:12:15.
Father is 3 times as old as the son. After 12 years he will be twice as old. Son’s present age is:
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Correct answer: D · 12 years
F=3S. 3S+12=2(S+12) ⇒ 3S+12=2S+24 ⇒ S=12.
Mixture & Percentage
4 exam-level questions · click any solution after you attempt
A 40-litre mixture is 20% alcohol. Alcohol to be added to make it 30% alcohol is:
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Correct answer: A · 40/7 litres
Alcohol now=8 L, water=32 L (fixed). (8+x)/(40+x)=0.3 → 8+x=12+0.3x → 0.7x=4 → x=40/7 L.
Milk and water in a vessel are in ratio 4 : 1. If 5 litres of water is added, ratio becomes 4 : 3. Original quantity of milk is:
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Correct answer: D · 10 L
Milk 4x, water x. 4x/(x+5)=4/3 => 12x=4x+20 => 8x=20 => x=2.5. Milk=10 L.
A number is increased by 20% and then decreased by 20%. Net change is:
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Correct answer: A · 4% decrease
Multiplier 1.2×0.8=0.96. Net 4% decrease.
If 30% of a number is 150, then 45% of the same number is:
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Correct answer: D · 225
Number=500. 45% of 500=225.
Mensuration & Probability
5 exam-level questions · click any solution after you attempt
Area of a circle with circumference 44 cm is (π=22/7):
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Correct answer: B · 154 cm²
2πr=44 ⇒ r=7. Area=πr²=22/7×49=154.
Volume of a cube of edge 6 cm is:
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Correct answer: A · 216 cm³
6³=216.
A die is thrown. Probability of getting a prime number is:
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Correct answer: A · 1/2
Primes on a die: 2,3,5 (three). 3/6=1/2.
Two coins are tossed. Probability of at least one head is:
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Correct answer: C · 3/4
HH, HT, TH, TT. At least one H: 3/4.
The HCF of 48 and 180 is:
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Correct answer: D · 12
48=2⁴×3; 180=2²×3²×5. HCF=2²×3=12.
Arithmetic Misc
3 exam-level questions · click any solution after you attempt
Average of first 10 natural numbers is:
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Correct answer: D · 5.5
n(n+1)/2 / n = (n+1)/2 = 11/2 = 5.5.
A man spends 80% of his income. If income is ₹25,000, savings are:
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Correct answer: A · ₹5,000
20% of 25,000 = 5,000.
The smallest number that must be added to 220 to make it a perfect square is:
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Correct answer: C · 5
14²=196, 15²=225. 225−220=5.
Quick answer key
Use this only after a timed attempt. Full working is under each question.
FAQs
How many Quant questions are asked in RBI Grade B Phase 1?
30 questions for 30 marks in 25 minutes, with 0.25 negative marking.
What is the most important Quant topic?
Data Interpretation. It has carried 10–17 questions in recent years. Number Series is the most reliable second cluster.
Is the Quant syllabus officially listed?
Not line by line. RBI describes the section as Quantitative Aptitude. The topic list on this page is reconstructed from previous papers.
What score should I target?
Clear the sectional cut-off first (often around 12–15). A comfortable Phase 1 profile is 20+ raw in Quant with high accuracy.
Ready to crack RBI Grade B 2027?
Use this page as your daily Quant gym. Pair it with Phase 2 ESI / FM notes and full mocks on CrackTarget.
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